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# gravitation class 9 questions

Mention any four phenomena that the universal law of gravitation was able to explain. Answer: Give reasons. This is because acceleration due to gravity is independent of the mass of the falling body. A stone is dropped from a cliff. What keeps the moon in uniform circular motion around the earth? 1. Differences between g andG. From a cliff of 49 m high, a man drops a stone. Two particles are placed at some distance. (d) Acceleration = 10 ms-2 Calculate the height of the building. Prove that if the earth attracts two bodies placed at same distance from the centre of the earth with the same force, then their masses are equal. Answer: Answer: The tides in the sea formed by the rising and falling of water level in the sea are due to the gravitational force of attraction which the sun and the moon exert on the water surface in the sea. This hypothesis is not correct. The earth and the moon are attracted to each other by gravitational force. At what place on the earth’s surface is the weight of a body maximum? or t = $$\frac{0.5}{9.8}$$ = 0.05 s. Question 11. So, v2 = u2 + 2gs, Will this ratio remain the same if (i) one of the objects is hollow and the other one is solid; and (ii) both of them are hollow, size remaining the same in each case? Clear your doubts and get step by step answers to the questions asked in the Xam Idea Class 9 textbook. Zero. Free PDF Download - Best collection of CBSE topper Notes, Important Questions, Sample papers and NCERT Solutions for CBSE Class 9 Physics Gravitation. If the mass of a body is 9.8 kg on the earth, what would be its mass on the moon? Answer: $$\frac{G \times M e \times m_{1}}{R^{2}}=\frac{G \times M_{e} \times m_{2}}{R^{2}}$$ Answer: Thus a big stone will fall with the same acceleration as a small stone. Gravitational constant is numerically equal to the force of attraction between two masses of 1 kg that are separated by a distance of 1 m. Answer: The mass of an object is the measure of its (a) pressure. v2 = 2gs = 2 × 9.8 × 100 = 1960 Question 15. Derive expression for force of attraction between two bodies and then define gravitational constant. (d) 360 kg. What would happen to your weight? Why does a body reach the ground quicker at poles than at the equator when dropped from the same height? This document is highly rated by Class 9 … Initial velocity, u = 0 ⇒ m1 = m2, Question 3. Log in, Concise Mathematics Class 10 ICSE Solutions 2018. Question 2. Answer: What is the source of centripetal force that a planet requires to revolve around the sun? Answer: (b) time of fall of the body? For the second stone, (e) Acceleration = -10 ms-2 “Every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.” Let us consider two bodies A and B of masses m1 and m2 which are separated by a distance r. Then the force of gravitation (F) acting on the two bodies is given by ⇒ Average density of the earth, D = $$\frac{\text { Mass }}{\text { Volume }}=\frac{g R^{2}}{G \times V e}$$ Question 9. Answer: Question 5. Answer: 1. Free PDF Download - Best collection of CBSE topper Notes, Important Questions, Sample papers and NCERT Solutions for CBSE Class 9 Physics Gravitation. Who formulated the universal law of gravitation? Question 5. [NCERT Exemplar] If the radius of the moon is 1.74 × 106 m, calculate the mass of the moon. Solve high order thinking questions related to gravitation and prepare for your exam in a better and easy way. Answer: Download Social Science Notes PDF for CBSE Class 6 to Class 10 Quick Revision, Science Notes | Quick Revision Notes for CBSE Class 6 to Class 10 Science – Free PDF Download, Download CBSE Maths Notes for 6 to 12 Classes | NCERT Maths Quick Revision Notes for Class 6 to 12 Free PDF, MCQ Questions for Class 11 Economics with Answers Chapter Wise PDF Download, Download All Chapters Social Science NCERT Solutions Pdf for Class 6 to Class 10, Science NCERT Solutions Class 6 to Class 10 Chapterwise Free PDF Download, Downlaod Free NCERT Solutions for Class 6 to Class 12 Maths | NCERT Maths Textbook Solutions PDF, Free Class 11 & Class 12 Chapterwise Physics NCERT Solutions PDF Download, Chapter Wise NCERT Chemistry Solutions for Class 12 and Class 11, Biology NCERT Solutions for Class 11 and Class 12 | Free PDF Download, Concise Mathematics Class 10 ICSE Solutions. Prove that if a body is thrown vertically upward, the time of ascent is equal to the time of descent. [NCERT Exemplar] MCQ on gravitation.> In this post I come up with some important general knowledge questions with answers on a very crucial topic called Gravitation.These multiple choice questions are very important for upcoming exams for general science like SSC, CGL, CHSL, MTS, Railway Group-D, Group-C, IAS, UPSC Air force and Navy. Question 16. v = u + gt2 = 0 – (0.5)2 = 2 × (-9.8) × h Acceleration, g = – 9.8 m/s2 Question 2. Gravitation | NCERT Exercises, Questions 10, 11 & 12 | CBSE Class 9 Physics | Science Chapter 10 | Vedantu Class 9 and 10. When hypothetically M becomes 4 M and R becomes $$\frac{R}{2}$$. Question 9. 3. Lactometer works on Archimede’s principle. Dividing equation (1) by (2), we get Question 4. The earth attracts the moon with a force that is: (a) More than that exerted … Weight of the same body on the earth’s surface will be Zero. Online test of Chapter 10 Gravitation 3 Science| Class 9th Questions : 1. where G is a constant known as universal gravitational constant. Which stone would reach the ground first and why? Class 9 Physics Notes - Chapter 5 - Gravitation - Numerical Problems. Online Test for Class 9 Physics Gravitation . (ii) As v = u2 + 2 gs All Gravitation Exercise Questions with Solutions to help you to revise complete Syllabus and Score More marks. Question 5. Question 11. The acceleration due to gravity does not depend upon the mass of the stone or body. Original weight, W0 = mg = mG $$\frac{M}{R^{2}}$$ Question 4. Answer: Question 7. Gravitational force. Take g = 9.8 m/s2. The mass of moon is about 0.012 times that of the earth and its […] (2) If the average distance between the Sun and the Earth is 1.5 x 10 11 m, calculate the force exerted by the Sun on the Earth and also by Earth on the Sun. Download CBSE Class 9 Physics Gravitation MCQs in pdf, Physics chapter wise Multiple Choice Questions free, Question: The mass of an object isa) The amount of matter contained in the object, independent of where that object is foundb) the force of gravity on that object located at a particular point in spacec) dependent on whether the object is on the Earth or elsewhere.d) Question 3. It is different at different places on the surface of the earth. Answer: From (1) and (2), we get t1 = t2 (a) No % Variation in the weight of a body = % Change in g = 0.7%. Question 1: A body weights 700 g wt. (c) At point B Why? Assume that g = 10 m/s2 and that there is no air resistance. i.e., the second stone was thrown downward with a speed of 12.1 ms-1. Time taken to reach the ground, t = 4 s Find out the ratio of time they would take in reaching the ground. i.e., First stone would take 3.16 s to reach the ground. What will be its speed when it has fallen 100 m? 2. Answer: Features of Xam Idea Class 9 Science Solutions. G = F To design hydrometers to find the density of liquids. 1 ] Find the gravitational force of attraction between a body of unit mass and the Moon. Answer: Question 1. Answer: This solution contains questions, answers, images, step by step explanations of the complete Chapter 10 titled Gravitation of Science taught in class 9. Answer: The acceleration produced in a body falling freely under the action of the gravitational pull of the Earth is known as acceleration due to gravity. The value of is different at different points on the Earth. At the equator. The position of required point is at a distance of 4 m from mass of 3 kg. Moreover, with help of these questions students may revise important fundamental concepts involved in Gravitation chapter. Here, s = 100 m, u = 0 Answer: Question 19. We know from Newton’s second law of motion that the force is the product of mass and acceleration. = $$20 \sqrt{2}$$ms-1, Question 6. Question 1. Gravitation Objective GK Questions and Answers. The reason for the formation of tides in sea is the gravitational attraction of the moon. Question 18. (b) No. If its least count is 1/2 ml then the space between 5ml and 10ml mark should be divided into or D = $$\frac{g R^{2}}{G \frac{4}{3} \pi R^{3}}=\frac{3 g}{4 \pi G R}$$, Question 6. Calculate the value of acceleration due to gravity g using the relation between g and G. Answer: Register online for Science tuition on Vedantu.com to score more marks in your examination. Answer: (b) 60 kg. (c) inertia. Sumeet is an intelligent boy and has good knowledge of science. They both hit the ground at the same time. Show that the weight of an object on the moon is $$\frac{1}{6}$$ th of its weight on the earth. When body is at a distance V from centre of the earth then g = $$\frac{G M}{r^{2}}$$. Answer: This object was carried to the moon. Physics-Gravitation & Pressure: Questions 1-5 of 43. Answer: 6.7 × 10-11 Nm2 kg-2) everywhere in the universe. Free Question Bank for 9th Class Science Gravitation and Floatation Gravitation Q2. The gravitational force between two bodies of unit masses separated by a init distance is known as universal gravitational constant. Question 9. Question 1. The value of ‘G’ is same at every point on the Earth. Weightlessness is a state when an object does not weigh anything. where Me = mass of earth and Re = radius of earth. At what place on the earth’s surface is the weight of a body minimum? Dec 15, 2020 - Practice Questions, Gravitation, Class 9, Science | EduRev Notes is made by best teachers of Class 9. 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Wm = $$\frac{G M_{m} m}{R_{m}^{2}}$$ …(1) When does an object show weightlessness? Question 21. The mass of the Sun is 2 x 10 30 kg and that of the Earth is 6 x 10 24 kg. Answer: The constant ‘G’ is universal because it is independent of the nature and sizes of bodies, the space where they are kept and at the time at which the force is considered. As u = 0, h1 = $$\frac{1}{2} g t_{1}^{2}$$ The weight of a … Find the percentage change in the weight of a body when it is taken from the equator to the poles. (f) Acceleration = 10 ms-2 ans F ∝ $$\frac{1}{r^{2}}$$ ..(2) [NCERT Exemplar] Does the apple also attract the earth? The entire NCERT textbook questions have been solved by best teachers for you. Answer. Question 10. NCERT Solutions for Class 9 Science Chapter 10 - Gravitation [FREE]. 0 = 0.5 – 9.8t As we know s = ut + $$\frac{1}{2}$$ gt2 Galileo Galilei. $$\frac{\iota_{1}}{t_{2}}=\sqrt{\frac{h_{1}}{h_{2}}}$$ F = $$G \frac{m M}{R^{2}}$$ …..(1) The earth is acted upon by gravitation of sun, even though it does not fall into the sun. The force of gravity decreases with altitude. If the earth attracts two objects with equal force, can we say that their masses must be equal? or h = $$\frac{0.25}{19.6}$$ = 0.0127 m How does the force of attraction between the two bodies depend upon their masses and distance between them? Universal Law of Gravitation For Class 9. A student thought that two bricks tied together would fall faster than a single one under the action of gravity. Answer: ∴ New weight becomes 4 times. On what principle, does the lactometer works? (G = 6.67 × 1011 Nm2kg-2) A stone is dropped from the top of a 40 m high tower. (c) At which point is the bal 1 at its maximum height? Question 2. Thus, the gravitational constant G is numerically equal to the force of gravitation which exists between two bodies of unit masses kept at a unit distance from each other. One second later, he throws another stone. (i) As v = u + gt The mass of the body on the moon will be (a) 6 kg. Upthrust or buoyant force in the upward direction. If the mass of each of the two particles is doubled, keeping the distance between them unchanged, the value of gravitational force between them will be (a) $$\frac{1}{4}$$ times (b) 4 times (c) $$\frac{1}{2}$$ times (d) unchanged. Therefore, the body appears to be floating weightlessly. The astronaut and the spaceship are orbiting with same acceleration hence, the body does not exert any force on the sides of the spaceship. Question 9: If the distance between two bodies is doubled, the force of attraction F between them will be _____ (1/4) F . So, acceleration = $$\frac{\text { Force }}{\text { Mass }}=\frac{20}{1}$$ = 20 m/s2, Question 3. v = $$\sqrt{1960}$$m/s = 44.2 m/s. Mass of the earth, Me = 6 × 1024 kg Answer: MCQ Questions for Class 9 Science Chapter 10 Gravitation with Answers MCQs from Class 9 Science Chapter 10 – Gravitation are provided here to help students prepare for their upcoming Science exam. So, the earth does not fall into the sun. The notes contain solution of all the numerical given in the chapter. At the poles. Answer: If the small and big stones are dropped from the roof of a house simultaneously, they will reach the ground at the same time. The value of ‘g’ at the equator of the earth is lesser than that at poles. Points on the earth [ NCERT Exemplar Class 9 Science is very resource. Together would fall faster than a single one under the force of attraction between bodies! The sea surface is the weight of a 40 m high, a man drops a stone dropped the... 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Complete syllabus and score More marks, why does a body is thrown vertically upwards, what is weight... Defined as the ratio of the body appears to be floating weightlessly write down the shown... Is very important resource for students preparing for IX Board Examination with which the stone or body NCERT! Here we have provided NCERT Exemplar ] answer: According to Newton ’ s gravitational on! At point c in a state when an object is the bal l ’ acceleration! Same on the earth is lesser than that exerted … question 9 9th questions: 1 down... Answers to the time of fall of the bag or the suitcase to be floating.!, as previous trends have shown easy way h2, respectively is independent of density... The apparent loss in weight of an object is 60 kg on the moon its velocity! Reason for the formation of tides takes place in sea or ocean attraction of the substance the! Has fallen 100 m order thinking questions related to Gravitation and prepare for your exam in better! Provided in bags and suitcases vertically upward, the time of descent every year, as previous trends shown. In, Concise Mathematics Class 10 ICSE Solutions 2018 unit masses separated by a body is kg.